49x^2-150x+9=0

Solution for 49x^2-150x+9=0 equation:

49x^2-150x+9=0

a = 49; b = -150; c = +9;
Δ = b2-4ac
Δ = -1502-4·49·9
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-144}{2*49}=\frac{6}{98}
=3/49
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+144}{2*49}=\frac{294}{98}
=3
$